1-(1/x^2)=-3

Solution for 1-(1/x^2)=-3 equation:

1-(1/x^2)=-3

We move all terms to the left:

1-(1/x^2)-(-3)=0


Domain of the equation: x^2)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-(1/x^2)+4=0

We get rid of parentheses

-1/x^2+4=0

We multiply all the terms by the denominator


4*x^2-1=0

We add all the numbers together, and all the variables

4x^2-1=0

a = 4; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·4·(-1)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4}{2*4}=\frac{-4}{8}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4}{2*4}=\frac{4}{8}
=1/2
$